ICSE Class 9 Logarithms Solution New Pattern By Clarify Knowledge
ICSE Class 9 Logarithms Solution New Pattern 2022
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ICSE Class 9 Logarithms Solution Table
- ICSE Class 9 Logarithms Solution New Pattern By Clarify Knowledge
- OUR EBOOKS CAN HELP YOU ICSE CLASS 10 BOARD
- CODE IS EASY CAN HELP YOU IN SEMESTER 2
- ICSE Class 9 Logarithms Solution Table
- Chapter 8 - Logarithms Exercise Ex. 8(A)
- Chapter 8 - Logarithms Exercise Ex. 8(B)
- Chapter 8 - Logarithms Exercise Ex. 8(C)
- Chapter 8 - Logarithms Exercise Ex. 8(D)
Chapter 8 - Logarithms Exercise Ex. 8(A)
Question 1
Express each of the following in logarithmic form:
(i) 53 = 125
(ii) 3-2 =
(iii) 10-3 = 0.001
(iv) Solution 1
(i)

(ii)

(iii)

(iv)

Question 2
Express each of the following in exponential form:
(i) logg 0.125 = -1
(ii) log100.01 = -2
(iii) logaA = x
(iv) log101 = 0Solution 2
(i)

(ii)

(iii)

(iv)

Question 3
Solve for x: log10 x = -2.Solution 3

Question 4
Find the logarithm of:
(i) 100 to the base 10
(ii) 0.1 to the base 10
(iii) 0.001 to the base 10
(iv) 32 to the base 4
(v) 0.125 to the base 2
(vi) to the base 4
(vii) 27 to the base 9
(viii) to the base 27Solution 4
(i)

(ii)

(iii)

(iv)

(v)

(vi)

(vii)

(viii)

Question 5
State, true or false:
(i) If log10 x = a, then 10x = a.
(ii) If xy = z, then y = logzx.
(iii) log2 8 = 3 and log8 = 2 = .Solution 5
(i)

(ii)

(iii)

Question 6
Find x, if:
(i) log3 x = 0
(ii) logx 2 = -1
(iii) log9243 = x
(iv) log5 (x - 7) = 1
(v) log432 = x - 4
(vi) log7 (2x2 - 1) = 2Solution 6
(i)

(ii)

(iii)

(iv)

(v)

(vi)

Question 7
Evaluate:
(i) log10 0.01
(ii) log2 (1 ÷ 8)
(iii) log5 1
(iv) log5 125
(v) log16 8
(vi) log0.5 16Solution 7
(i)

(ii)

(iii)

(iv)

(v)

(vi)

Question 8
If loga m = n, express an - 1 in terms in terms of a and m.Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12
If log (x2 - 21) = 2, show that x = ± 11.Solution 12

Chapter 8 - Logarithms Exercise Ex. 8(B)
Question 1
Express in terms of log 2 and log 3:
(i) log 36 (ii) log 144 (iii) log 4.5
(iv) log - log
(v) log
log
+ log
Solution 1
(i)

(ii)

(iii)

(iv)

(v)

Question 2
Express each of the following in a form free from logarithm:
(i) 2 log x - log y = 1
(ii) 2 log x + 3 log y = log a
(iii) a log x - b log y = 2 log 3Solution 2
(i)

(ii)

(iii)

Question 3
Evaluate each of the following without using tables:
(i) log 5 + log 8 - 2 log 2
(ii) log108 + log1025 + 2 log103 - log1018
(iii) log 4 + log 125 -
log 32Solution 3
(i)

(ii)

(iii)

Question 4
Prove that:

Solution 4

Question 5
Find x, if:
x - log 48 + 3 log 2 = log 125 - log 3.Solution 5

Question 6
Express log102 + 1 in the form of log10x.Solution 6

Question 7
Solve for x:
(i) log10 (x - 10) = 1
(ii) log (x2 - 21) = 2
(iii) log (x - 2) + log (x + 2) = log 5
(iv) log (x + 5) + log (x - 5)
= 4 log 2 + 2 log 3Solution 7
(i)

(ii)

(iii)

(iv)

Question 8
Solve for x:
(i)
(ii)
(iii)
(iv) Solution 8
(i)

(ii)

(iii)

(iv)

Question 9
Given log x = m + n and log y = m - n, express the value oflog in terms of m and n.Solution 9

Question 10
State, true or false:
(i) log 1 log 1000 = 0
(ii)
(iii) If then x = 2
(iv) log x log y = log x + log ySolution 10
(i)

(ii)

(iii)

(iv)

Question 11
If log102 = a and log103 = b; express each of the following in terms of 'a' and 'b':
(i) log 12(ii) log 2.25(iii) log
(iv) log 5.4(v) log 60(iv) log Solution 11

(i)

(ii)

(iii)

(iv)

(v)

(vi)

Question 12
If log 2 = 0.3010 and log 3 = 0.4771; find the value of:
(i) log 12(ii) log 1.2(iii) log 3.6
(iv) log 15(v) log 25(vi) log 8Solution 12

(i)

(ii)

(iii)

(iv)

(v)

(vi)

Question 13
Given 2 log10 x + 1 = log10 250, find :
(i) x(ii) log10 2xSolution 13
(i)

(ii)

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Chapter 8 - Logarithms Exercise Ex. 8(C)
Question 1
If log10 8 = 0.90; find the value of:
(i) log10 4(ii) log
(iii) log 0.125Solution 1

(i)

(ii)

(iii)

Question 2
If log 27 = 1.431, find the value of :
(i) log 9(ii) log 300Solution 2

(i)

(ii)

Question 3
If log10 a = b, find 103b - 2 in terms of a.Solution 3

Question 4
If log5 x = y, find 52y+ 3 in terms of x.Solution 4

Question 5
Given: log3 m = x and log3 n = y.
(i) Express 32x - 3 in terms of m.
(ii) Write down 31 - 2y + 3x in terms of m and n.
(iii) If 2 log3 A = 5x - 3y; find A in terms of m and n.Solution 5

(i)

(ii)

(iii)

Question 6
Simplify:
(i) log (a)3 - log a
(ii) log (a)3 log aSolution 6
(i)

(ii)

Question 7
If log (a + b) = log a + log b, find a in terms of b.Solution 7

Question 8
Prove that:
(i) (log a)2 - (log b)2 = log . Log (ab)
(ii) If a log b + b log a - 1 = 0, then ba. ab = 10Solution 8
(i)

(ii)

Question 9
(i) If log (a + 1) = log (4a - 3) - log 3; find a.
(ii) If 2 log y - log x - 3 = 0, express x in terms of y.
(iii) Prove that: log10 125 = 3(1 - log102).Solution 9
(i)

(ii)

(iii)

Question 10

Solution 10

Question 11

Solution 11

Chapter 8 - Logarithms Exercise Ex. 8(D)
Question 1
If log a +
log b - 1 = 0, find the value of a9.b4.Solution 1

Question 2
If x = 1 + log 2 - log 5, y = 2 log3 and z = log a - log 5; find the value of a if x + y = 2z.Solution 2

Question 3
If x = log 0.6; y = log 1.25 and z = log 3 - 2 log 2, find the values of:
(i) x+y- z (ii) 5x + y - zSolution 3

(i)

(ii)

Question 4
If a2 = log x, b3 = log y and 3a2 - 2b3 = 6 log z, express y in terms of x and z.Solution 4

Question 5
If log (log a + log b), show that: a2 + b2 = 6ab.Solution 5

Question 6
If a2 + b2 = 23ab, show that:
log (log a + log b).Solution 6

Question 7
If m = log 20 and n = log 25, find the value of x, so that: 2 log (x - 4) = 2 m - n.Solution 7

Question 8
Solve for x and y ; if x > 0 and y > 0;log xy = log + 2 log 2 = 2.Solution 8

Question 9
Find x, if:
(i) logx 625 = -4
(ii) logx (5x - 6) = 2Solution 9
(i)
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(ii)
_SHR_files/20140923182253_image004.gif?ssl=1)
Question 10

Solution 10

Question 11
_SHR_files/20140923182253_image008.gif?ssl=1)
Solution 11
_SHR_files/20140923182253_image010.gif?ssl=1)
Question 12
_SHR_files/20140923182253_image012.gif?ssl=1)
Solution 12
_SHR_files/20140923182253_image014.gif?ssl=1)
Question 13
Given log10x = 2a and log10y = .
(i) Write 10a in terms of x.
(ii) Write 102b + 1 in terms of y.
(iii) If , express P in terms of x and y.Solution 13

Question 14
Solve:
log5(x + 1) - 1 = 1 + log5(x - 1).Solution 14
_SHR_files/20140923182253_image022.gif?ssl=1)
Question 15
Solve for x, if:
_SHR_files/20140923182253_image024.gif?ssl=1)
Solution 15
_SHR_files/20140923182253_image026.gif?ssl=1)
Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20

Solution 20

Question 21

Solution 21

Question 22

Solution 22
