ICSE Class 10 Study of Compounds D. Sulphuric Acid Solution By Clarify knowledge
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ICSE Class 10 Study of Compounds D. Sulphuric Acid Solution Table
- ICSE Class 10 Study of Compounds D. Sulphuric Acid Solution By Clarify knowledge
- ICSE Class 10 Study of Compounds D. Sulphuric Acid Solution Table
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- Chapter 11 - Study of Compounds D. Sulphuric Acid Exercise Ex. 11
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Chapter 11 - Study of Compounds D. Sulphuric Acid Exercise Intext 1
Comment, sulphuric acid is referred to as
(a) King of chemicals
(b) Oil of vitriolSolution 1
(a) Sulphuric acid is called King of Chemicals because there is no other manufactured compound which is used by such a large number of key industries.
(b) Sulphuric acid is referred to as Oil of vitriol as it was obtained as an oily viscous liquid by heating crystals of green vitriol.Question 2
Sulphuric acid is manufactured by contact process
(a) Give two balanced equations to obtain SO2 in this process.
(b) Give the conditions for the oxidation of SO2
(c) Name the catalyst used.
(d) Why H2SO4 is not obtained by directly reacting SO3 with water.
(e) Name the chemical used to dissolve SO3 and also name the product formed.
(f) Name a gas that can be oxidized to sulphur.
(a) Two balanced equations to obtain SO2 is:
(i) 4FeS2 + 11O2 2Fe2O3 +8SO2
(ii) S +O2 SO2
(b) The conditions for the oxidation of SO2 are:
(i) The temperature should be as low as possible. The yield has been found to be maximum at about 4100C-450oC
(ii) High pressure (2 atm) is favoured because the product formed has less volume than reactant.
(iii) Excess of oxygen increases the production of sulphur trioxide.
(iv) Vanadium pentoxide or platinised asbestos is used as catalyst.
(c) Vanadium pentoxide (V2O5)
(d) Sulphuric acid is not obtained directly by reacting SO3 with water because the reaction is highly exothermic which produce the fine misty droplets of sulphuric acid that is not directly absorbed by water.
(e)The chemical used to dissolve SO3 is concentrated sulphuric acid. The product formed is oleum.
(f) Hydrogen sulphide.Question 3
Why the impurity of arsenic oxide must be removed before passing the mixture of SO2 and air through the catalytic chamber?Solution 3
Impurity of ARSENIC poisons the catalyst [i.e. deactivates the catalyst]. So, it must be removed before passing the mixture of SO2 air through the catalytic chamber.Question 4
(a) Name the catalyst which helps in the conversion of sulphur dioxide to sulphur trioxide in step C.
(b) In the contact process for the manufacture of sulphuric acid, sulphur trioxide is not converted to sulphuric acid by reacting it with water. Instead a two -steps procedure is used. Write the equations for the two steps involved in D.
(c) What type of substance will liberate sulphur dioxide from sodium sulphite in step E?
(d) Write the equation for the reaction by which sulphur dioxide is converted to sodium sulphite in step F.Solution 4
(a) The catalyst which helps in the conversion of sulphur dioxide to sulphur trioxide in step C is Vanadium pentoxide.
(b) The two steps for the conversion of sulphur trioxide to sulphuric acid is:
(i) SO3 + H2SO4H2S2O7
(ii) H2S2O7 + H2O 2H2SO4
(c)The substance that will liberate sulphur dioxide in step E is dilute H2SO4.
(d) The equation for the reaction by which sulphur dioxide is converted to sodium sulphite in step F is:
Chapter 11 - Study of Compounds D. Sulphuric Acid Exercise Ex. 11
Why is water not added to concentrated H2SO4 in order to dilute it?Solution 1
Water is not added to concentrated acid since it is an exothermic reaction. If water is added to the acid, there is a sudden increase in temperature and the acid being in bulk tends to spurt out with serious consequences.Question 2
Give two balanced reactions of each type to show the following properties of sulphuric acid.
(a) Acidic nature
(b) Oxidising agent
(d) Non-volatile natureSolution 2
Balanced reactions are:
(a) Acidic nature:
(i) Dilute H2SO4 reacts with basic oxides to form sulphate and water.
2 NaOH+H2SO4 Na2SO4+2H2O
(ii) CuO+H2SO4 CuSO4+H2O
(iii) It reacts with carbonate to produce CO2.
(b) Oxidising agent:
H2SO4 H2O +SO2 +[O]
Nascent oxygen oxidizes non-metals, metals and inorganic compounds.
Carbon to carbon dioxide
C+H2SO4 CO2 +H2O +2SO2
Sulphur to sulphur dioxide
S +H2SO4 3SO2 +2H2O
(d) Non-volatile nature:
It has a high boiling point (356oC) so it is considered to be non-volatile. Therefore, it is used for preparing volatile acids like hydrochloric acid, nitric acid from their salts by double decomposition reaction.
NaCl + H2SO4NaHSO4 +HCl
KCl + H2SO4 KHSO4 +HClQuestion 3
Give a chemical test to distinguish between:
(a) Dilute sulphuric acid and dilute hydrochloric acid
(b) Dilute sulphuric acid and conc.sulphuric acidSolution 3
(a)Bring a glass rod dipped in Ammonia solution near the mouth of each test tubes containing dil. Hel and dil. H2SO4each.
|Dil HCl||Dil. H2SO4|
|White fumes of ammonium chloride||No such fumes|
1. Dilute sulphuric acid treated with zinc gives Hydrogen gas which bums with pop sound.
Concentrated H2SO4 gives SO2 gas with zinc and the gas turns Acidified potassium dichromate paper green.
2.Barium chloride solution gives white ppt. with dilute H2SO4, This white ppt. is insoluble in all acids.
Concentrated H2SO4 and NaCl mixture when heated gives dense white fumes if glass rod dipped in Ammonia solution is brought near it.Question 4
Name the products formed when hot and concentrated sulphuric acid reacts with the following:
(e) CopperSolution 4
(a) When sulphuric acid reacts with sulphur the product formed is Sulphur dioxide is formed.
S +2H2SO4 3SO2 + 2H2O
(b) When sulphuric acid reacts with sodium hydroxide it neutralizes base to form sodium sulphate.
2NaOH + H2SO4 Na2SO4 + 2H2O
(c) When sulphuric acid reacts with sugar it forms carbon
C12 H22O1112C + 11H2O
(d) When sulphuric acid reacts with carbon it forms carbon dioxide and sulphur dioxide gas.
C +2H2SO4 CO2 + 2H2O + 2SO2
(e) When sulphuric acid reacts with copper it forms copper sulphate and sulphur dioxide.
Cu + H2SO4 CuSO4 + 2H2O + SO2 Question 5
(a) Concentrated sulphuric acid kept in air tight bottles?
(b) H2SO4 is not a drying agent for H2S?
(c) Sulphuric acid used in the preparation of HCl and HNO3? Give equation in both cases.Solution 5
(a) Concentrated sulphuric acid is hygroscopic substance that absorbs moisture when exposed to air. Hence, it is stored in air tight bottles.
(b) Sulphuric acid is not a drying agent for H2S because it reacts with H2S to form sulphur.
(c) Concentrated sulphuric acid has high boiling point (356oC). So, it is considered to be non-volatile. Hence, it is used for preparing volatile acids like Hydrochloric acid and Nitric acids from their salts by double decomposition.
NaNO3 +H2SO4NaHSO4 +HNO3Question 6
What property of conc. H2SO4 is made use of in each of the following cases? Give an equation for the reaction in each case
(a) In the production of HCl gas when it reacts with a chlorine
(b) In the preparation of CO from HCOOH
(c) As a source of hydrogen by diluting it and adding a strip of magnesium
(d) In the preparation of sulphur dioxide by warming a mixture of conc. Sulphuric acid and copper -turnings.
(e) Hydrogen sulphide gas is passed through concentrated sulphuric acid
(f) Its reaction with (i) ethanol (ii) carbonSolution 6
(a) Due to its reducing property. i.e, it is a non-volatile acid.
NaCl+ H2SO4NaHSO4 + HCl
(b) It is a dehydrating agent.
HCOOH CO + H2O
(c) Magnesium is present above hydrogen in the reactivity series so sulphuric acid is able to liberate hydrogen gas by reacting with magnesium strip.
Mg + H2SO4 MgSO4+H2
(d) Due to its oxidizing character
Cu +H2SO4 CuSO4 +2H2O +SO2
(e) Due to its oxidizing property Hydrogen sulphide gas is passed through concentrated sulphuric acid to liberate sulphur dioxide and sulphur is formed.
H2S + H2SO4 S + 2H2O + SO2
What is the name given to the salts of:
(a) Sulphurous acid
(b) Sulphuric acidSolution 7
The name of the salt of
(a) Hydrogen sulphites and Sulphites.
(b) Sulphate and bisulphate.Question 8
Give reasons for the following.
(a) Sulphuric acid forms two types of salts with NaOH
(b) Red brown vapours are produced when concentrated sulphuric acid is added to hydrogen bromide.
(c) A piece of wood becomes black when concentrated sulphuric acid is poured on it
(d) Brisk effervescence is seen when oil of vitriol is added to sodium carbonate.Solution 8
(a) Two types of salts are formed when sulphuric acid reacts with NaOH because sulphuric acid is dibasic.
NaOH + H2SO4 NaHSO4 + H2O
2NaOH + H2SO4Na2SO4 + 2H2O
(b) When hydrogen bromide reacts with sulphuric acid the bromine gas is obtained which produce red brown vapours.
2KBr+3H2SO4 2KHSO4+SO2+Br2 +2H2O
(c) A piece of wood becomes black when concentrated sulphuric acid is poured on it because it gives a mass of carbon.
(d) When sulphuric acid is added to sodium carbonate it liberates carbon dioxide which produces brisk effervescence.
Na2CO3+H2SO4Na2SO4 +H2O+CO2 Question 9
Copy and complete the following table:
|Column 1Substance reacted with acid||Column 2Dilute or concentrated acid||Column 3Gas|
|Column 1Substance reacted with acid||Column 2Dilute or concentrated acid||Column 3Gas|
|Substance reacted with acid||Dilute or concentrated sulphuric acid||Gas|
|Zinc||Dilute sulphuric acid||Hydrogen|
|Calcium carbonate||Concentrated sulphuric acid||Carbon dioxide|
|Bleaching power CaOCl2||Dilute sulphuric acid||only chlorine|
Following are the typical properties of dilute acid complete them by inserting suitable words:
(i) Active metal + Acid ⟶…………. + …………….
(ii) Base + Acid ⟶ ……….. + ………….
(iii) Carbonate/hydrogen carbonate + Acid ⟶ ……….+ ………….+……….
(iv) Sulphite/hydrogen sulphite + Acid ⟶ ………..+………….+………..
(v) Sulphite + Acid ⟶ ……….. +………….Solution 10
(i) Active metal + Acid ⟶ Metal sulphate + Hydrogen
(ii) Base + Acid ⟶ Salt + Water
(iii) Carbonate/hydrogen carbonate + Acid ⟶ Salt + Water + Carbon dioxide
(iv) Sulphite/hydrogen sulphite + Acid ⟶ Salt + Water + Sulphur dioxide
(v) Sulphite + Acid ⟶ Salt + Hydrogen sulphideQuestion 11(a)
Which property of sulphuric acid accounts for its use as a dehydrating agent?Solution 11(a)
Sulphuric acid is powerful dehydrating agent on account of its strong affinity towards water.Question 11(b)
Concentrated sulphuric acid is both an oxidizing agent and a non-volatile acid. Write one equation. Each to illustrate the above mentioned properties of sulphuric acid.Solution 11(b)
Concentrated sulphuric acid as
i. Oxidising agent:
The oxidising property of conc. sulphuric acid its due to the fact that on thermal decomposition, it yeilds nacent oxygen [O].
H2SO4→ H2O + SO2 + [O]
ii. Non-volatile acid:
conc. sulphuric acid has high boiling point (338°C) that why it is said to be a non volitile compound, therefore it is used for preparing volatile acids like hydrochloric acids, nitric acids from there salts by double decomposition
H2SO4 + NaCl → NaHSO4 + HClQuestion 12
Some properties of sulphuric acid are listed below. Choose the property A, B, C or D which is responsible for the reactions (i) to (v). Some properties may be repeated:
B. Dehydrating agent
C. Non-volatile acid
D. Oxidising agent
(i) C12H22O11 +nH2SO4 12C + 11H2O + nH2SO4
(ii) S + 2H2SO4 3SO2 +2H2O
(iii) NaCl +H2SO4 NaHSO4 + HCl
(iv) CuO + H2SO4 CuSO4 +H2O
(v) Na2CO3 + H2SO4 Na2SO4 + H2O +CO2Solution 12
(v) AQuestion 13
(a) Name the acid formed when sulphur dioxide dissolves in water.
(b) Name the gas released when sodium carbonate is added to a solution of sulphur dioxide.Solution 13
(a) The acid formed when sulphur dioxide dissolves in water is sulphurous acid.
(b) Carbondioxide gas is released when sodium carbonate is added to solution of sulphur dioxide.Question 2008
- Dilute sulphuric acid will produce a white precipitate when added to a solution of :
i. Copper nitrate
ii. Zinc nitrate
iii. Lead nitrate
iv. Sodium nitrate
- Identify the following substance: Liquid E can be dehydrated to produce ethene.
c. Copy and complete the following table relating to an important industrial process and its final output.
|Name of process||Inputs||Catalyst||Equation for catalyzed reaction output|
|Contact process||Sulphur dioxide + oxygen|
- Making use only of substances given : dil. sulphuric acid, sodium carbonate, zinc, sodium. sulphite, lead, calcium carbonate : Give equations for the reactions by which you could obtain :
ii. sulphur dioxide
iii. carbon dioxide
iv. zinc carbonate [2 steps]
- What property of conc. H2SO4 :
i. is used in the action when sugar turns black in its presence.
ii. allows it to be used in the preparation of HCl and HNO3 acids.
f. Write the equations for :
i. dil. H2SO4 and barium chloride
ii. dil. H2SO4 and sodium sulphuideSolution 2008
a. (C) Lead nitrate
b. Liquid E is Ethanol.
|Name of process||Inputs||Catalyst||Equation for catalyzed reaction output||output|
|Contact process||Sulphur dioxide + oxygen||Platinum or V2O5||2SO2 + O2 ⇄ 2SO3||Sulphuric acid|
i. Zn + dil. H2SO4→ ZnSO4 + H2
ii. Na2CO3 + dil. H2SO4→ Na2SO4 + H2O + CO2
iii. Pb(NO3) + dil. H2SO4→ PbSO4 + 2HNO3
iv. Zn + dil. H2SO4→ ZnSO4 + H2
ZnSO4 + Na2CO3→ ZnCO3 + Na2SO4
i. The property of concentrated sulphuric acid which allows it to be used in is used in the action when sugar turns black in its presence is its dehydrating property.
ii. The property of concentrated sulphuric acid which allows it to be used in the preparation of hydrogen chloride and nitric acid is its non-volatility.
H2SO4 + BaCl2 → BaSO4 + 2HClQuestion 2009
a. Name the gas evolved [formula is not acceptable]. The gas that can be oxidised to sulphur.Solution 2009
Hydrogen ChlorideQuestion 2010
a. Give the equation for :
i. Heat on sulphur with conc. sulphuric acid
ii. Reaction of - sugar with conc. sulphuric acid.
b. Give a balanced equation for the conversion of zinc oxide to zinc sulphate.
c. Select the correct answer from A, B, C.
A. Sodium hydroxide solution
B. A weak acid
C. Dilute sulphuric acid.
The solution which liberates sulphur dioxide gas, from sodium sulphite.Solution 2010
i. S + H2SO4 → 3SO2 +2H2O.
ii. C12H22O11 + Conc. H2SO4 → 6C + 6H2O
b. ZnO + H2SO4 → ZnSO4 + H2O.
c. C) Dilute sulphuric acid. Question 2011
a. State your observation when - Sugar crystals are added to a hard glass test tube containing conc. sulphuric acid.
b. Choose the correct answer from the choices - The gas evolved when dil. sulphuric acid reacts with iron sulphide.
i. Hydrogen sulphide
ii. Sulphur dioxide
iii. Sulphur trioxide
iv. Vapour of sulphuric acid
c. Give a balanced equation for :
i. Dilute sulphuric acid is poured over sodium sulphite.
ii. Manufacture of sulphuric acid by the - contact process.
d. State the property of sulphuric acid shown by the reaction of conc. sulphuric acid when heated with
i. potassium nitrate
ii. carbonsSolution 2011
a. Charring of sugar takes place. Sulphuric acid dehydrates sugar leaving behind carbon which is black in colour.
b. i. Hydrogen sulphide
i. Non-volatile nature
ii. as an oxidising agentQuestion 2012
a. Name - The gas produced on reaction of dilute sulphuric acid with a metallic sulphide.
b. Some properties of sulphuric acid are listed below. Choose the role played by sulphuric acid as A, B, C or D which is responsible for the reactions (i) to (v). Some role/s may be repeated.
1. Dilute acid
2 Dehydrating agent
3. Non-volatile acid
4. Oxidising agent
c. Give balanced equation for the reaction : Zinc sulphide and dilute sulphuric acid.Solution 2012
a. Hydrogen Sulphide (H2S).
i. (B) Dehydrating agent
ii. (D) Oxidising agent
iii. (C) Non-volatile acid
iv. (A) Dilute acid
v. (D) Oxidising agent
c. ZnS + dil.H2SO4→ ZnSO4 + H2SQuestion 2013
a. State one appropriate observation for : Conc. H2SO4 is added to a crystal of hydrated copper sulphate.
b. In the given equation - S + 2H2SO4→ 3SO2 + 2H2O :
Identify the role played by conc. H2SO4.
i. Non-volatile acid
ii. Oxidising agent
iii. Dehydrating agent
iv. None of the above
c. Give a balanced equation for : Dehydration of concentrated sulphuric acid with sugar crystals.
d. Identify the substance underlined : A dilute mineral acid which forms a white precipitate when treated with barium chloride solution.Solution 2013
a. when Conc. H2SO4 is added to a crystal of hydrated copper sulphate,it removes water of crystalisation from salt.
b. ii. Oxidising agent
c. C12H22O11 + Conc. H2SO4 → 6C + 6H2O
d. Sulphuric acid (H2SO4)Question 2014
a. Write balanced equations for the following : Action of concentrated sulphuric acid on carbon.
b. Distinguish between the following pairs of compounds using the test given within brackets. Dilute sulphuric acid and dilute hydrochloric acid [using barium chloride solution].
c. State the conditions required for the following reactions to take place : The conversion of sulphur dioxide to sulphur trioxde.
d. Give one equation each to show the following properties of sulphuric acid :
i. Dehydrating property
ii. Acidic nature
iii. As a non-volatile acidsSolution 2014
a. C + H2SO4 → CO2 + 2H2O + 2SO2.
b. Sulphuric acid precipitates the insoluble sulphate of barium from the solution of barium chloride.
BaCl2 + H2SO4→ BaSO4 + 2HCl
Dilute HCl does not react with barium chloride solution, and thus, no precipitate is produced in the reaction.
c. Two conditions for the conversion of sulphur dioxide to sulphur trioxide is as follows:
Temperature: 450-500° C Catalyst: V2O5
i. Dehydrating property of sulphuric acid:
H2SO4 has a great affinity for water, and therefore, it acts as a dehydrating agent.
ii. Acidic nature of sulphuric acid:
It acts as a strong dibasic acid.
H2SO4→ 2Hi+ + SO42-
It reacts with metals, metal oxides, metal hydroxides, carbonates etc. to form metallic sulphates and hydrogen at ordinary temperature.
Mg + H2SO4→ MgSO4 + H2↑
CuO + H2SO4→ CuSO4 + H2O
2NaOH + H2SO4→ Na2SO4 + 2H2O
ZnCO3 + H2SO4→ ZnSO4 + H2O + CO2↑
iii. As a non-volatile acid:
It has a high boiling point, so it is used to prepare volatile acids such as HCl, HNO3 and acetic acid from their salts.
NaCl + H2SO4→ NaHSO4 + HCl
NaNO3 + H2SO4→ NaHSO4 + HNO3
CH3COONa + H2SO4→ NaHSO4 + CH3COOHQuestion 2015
(a) In the manufacture of sulphuric acid by contact process, give the equations for the conversion of sulphur trioxide to sulphuric acid.
(b) Give equations for the action of sulphuric acid on
(i) Potassium hydrogen carbonate
(c) Identify the acid in each case.
(i) Acid which produces sugar charcoal from sugar
(ii) Acid on mixing with lead nitrate solution produces white ppt. which is insoluble even on heatingSolution 2015
(a) In the contact process for the manufacture of sulphuric acid, the equations for the conversion of sulphur trioxide to sulphuric acid are
SO3 + H2SO4 → H2S2O7
(oleum or pyrosulphuric acid)
H2S2O7 + H2O → 2H2SO4
(i) Action of sulphuric acid on potassium hydrogen carbonate
2KHCO3+ H2SO4→ K2SO4+ 2H2O + 2CO2↑
(ii) Action of sulphuric acid on sulphur
S + 2H2SO4→ 3SO2 + 2H2O
(i) Concentrated sulphuric acid
(ii) Concentrated sulphuric acid