ICSE Class 10 Mensuration MCQ New Pattern
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ICSE Class 10 Mensuration MCQ Table
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ICSE Class 10 Mensuration MCQ HERE
1. The shape of an ice-cream cone is a combination of:
(a) Sphere + cylinder
(b) Sphere + cone
(c) Hemisphere + cylinder
(d) Hemisphere + cone
Answer: (d) Hemisphere + cone
The shape of an ice-cream cone is a combination of a hemisphere and a cone.
2. If a cone is cut parallel to the base of it by a plane in two parts, then the shape of the top of the cone will be a:
(a) Sphere
(b) Cube
(c) Cone itself
(d) Cylinder
Answer: (c) Cone itself
Explanation: If we cut a cone into two parts parallel to the base, then the shape of the upper part remains the same.
3. If we cut a cone in two parts by a plane parallel to the base, then the bottom part left over is the:
(a) Cone
(b) Frustum of cone
(c) Sphere
(d) Cylinder
Answer: (b) Frustum of cone
Explanation: See the figure below
4. If r is the radius of the sphere, then the surface area of the sphere is given by;
(a) 4 π r2
(b) 2 π r2
(c) π r2
(d) 4/3 π r2
Answer: (a) 4 π r2
If r is the radius of the sphere, then the surface area of the sphere is given by 4 π r2.
5. If we change the shape of an object from a sphere to a cylinder, then the volume of cylinder will
(a) Increase
(b) Decrease
(c) Remains unchanged
(d) Doubles
Answer: (c) Remains unchanged
Explanation: If we change the shape of a three-dimensional object, the volume of the new shape will be same.
6. Fifteen solid spheres are made by melting a solid metallic cone of base diameter 2cm and height 15cm. The radius of each sphere is:
(a) ½
(b) ¼
(c) 1/3√2
(d) 1/3√4
Answer: (d) 1/3√4
Explanation: Volume of 15 spheres = Volume of a cone
15 x (4/3) π r3 = ⅓ πr2h
5×4 π r3 = ⅓ π 12(15)
20r3 = 5
r3 = 5/20 = ¼
r = 1/3√4
7. The radius of the top and bottom of a bucket of slant height 35 cm are 25 cm and 8 cm. The curved surface of the bucket is:
(a) 4000 sq.cm
(b) 3500 sq.cm
(c) 3630 sq.cm
(d) 3750 sq.cm
Answer: (c) 3630 sq.cm
Explanation: Curved surface of bucket = π(R1 + R2) x slant height (l)
Curved Surface = (22/7) x (25 + 8) x 35
CSA = 22 x 33 x 5 = 3630 sq.cm.
8. If a cylinder is covered by two hemispheres shaped lid of equal shape, then the total curved surface area of the new object will be
(a) 4πrh + 2πr2
(b) 4πrh – 2πr2
(c) 2πrh + 4πr2
(d) 2πrh + 4πr
Answer: (c) 2πrh + 4πr2
Explanation: Curved surface area of cylinder = 2πrh
The curved surface area of hemisphere = 2πr2
Here, we have two hemispheres.
So, total curved surface area = 2πrh + 2(2πr2) = 2πrh + 4πr2
9. A tank is made of the shape of a cylinder with a hemispherical depression at one end. The height of the cylinder is 1.45 m and radius is 30 cm. The total surface area of the tank is:
(a) 30 m
(b) 3.3 m
(c) 30.3 m
(d) 3300 m
Answer: (b) 3.3 m
Explanation: Total surface area of tank = CSA of cylinder + CSA of hemisphere
= 2πrh + 2πr2= 2π r(h + r)
= 2 x 22/7 x 30(145 + 30) cm2
=33000 cm2
= 3.3 m2
10. If we join two hemispheres of same radius along their bases, then we get a;
(a) Cone
(b) Cylinder
(c) Sphere
(d) Cuboid
Answer: (c) Sphere