  ICSE Class 10 Mensuration MCQ New

## ICSE Class 10 Mensuration MCQ New Pattern

ICSE Class 10 Mensuration MCQ By Clarify Knowledge

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## ICSE Class 10 All Subject MCQ

### ICSE Class 10 Mensuration MCQ HERE

1. The shape of an ice-cream cone is a combination of:

(a) Sphere + cylinder

(b) Sphere + cone

(c) Hemisphere + cylinder

(d) Hemisphere + cone

The shape of an ice-cream cone is a combination of a hemisphere and a cone.

2. If a cone is cut parallel to the base of it by a plane in two parts, then the shape of the top of the cone will be a:

(a) Sphere

(b) Cube

(c) Cone itself

(d) Cylinder

Explanation: If we cut a cone into two parts parallel to the base, then the shape of the upper part remains the same.

3. If we cut a cone in two parts by a plane parallel to the base, then the bottom part left over is the:

(a) Cone

(b) Frustum of cone

(c) Sphere

(d) Cylinder

Explanation: See the figure below

4. If r is the radius of the sphere, then the surface area of the sphere is given by;

(a) 4 π r2

(b) 2 π r2

(c) π r2

(d) 4/3 π r2

If r is the radius of the sphere, then the surface area of the sphere is given by 4 π r2.

5. If we change the shape of an object from a sphere to a cylinder, then the volume of cylinder will

(a) Increase

(b) Decrease

(c) Remains unchanged

(d) Doubles

Explanation: If we change the shape of a three-dimensional object, the volume of the new shape will be same.

6. Fifteen solid spheres are made by melting a solid metallic cone of base diameter 2cm and height 15cm. The radius of each sphere is:

(a) ½

(b) ¼

(c) 1/3√2

(d) 1/3√4

Explanation: Volume of 15 spheres = Volume of a cone

15 x (4/3) π r= ⅓ πr2h

5×4 π r= ⅓ π 12(15)

20r= 5

r= 5/20 = ¼

r = 1/3√4

7. The radius of the top and bottom of a bucket of slant height 35 cm are 25 cm and 8 cm. The curved surface of the bucket is:

(a) 4000 sq.cm

(b) 3500 sq.cm

(c) 3630 sq.cm

(d) 3750 sq.cm

Explanation: Curved surface of bucket = π(R+ R2) x slant height (l)

Curved Surface = (22/7) x (25 + 8) x 35

CSA = 22 x 33 x 5 = 3630 sq.cm.

8. If a cylinder is covered by two hemispheres shaped lid of equal shape, then the total curved surface area of the new object will be

(a) 4πrh + 2πr2

(b) 4πrh – 2πr2

(c) 2πrh + 4πr2

(d) 2πrh + 4πr

Explanation: Curved surface area of cylinder = 2πrh

The curved surface area of hemisphere = 2πr2

Here, we have two hemispheres.

So, total curved surface area = 2πrh + 2(2πr2) = 2πrh + 4πr2

9. A tank is made of the shape of a cylinder with a hemispherical depression at one end. The height of the cylinder is 1.45 m and radius is 30 cm. The total surface area of the tank is:

(a) 30 m

(b) 3.3 m

(c) 30.3 m

(d) 3300 m

Explanation: Total surface area of tank = CSA of cylinder + CSA of hemisphere

= 2πrh + 2πr2= 2π r(h + r)

= 2 x 22/7 x 30(145 + 30) cm2

=33000 cm2

= 3.3 m2

10. If we join two hemispheres of same radius along their bases, then we get a;

(a) Cone

(b) Cylinder

(c) Sphere

(d) Cuboid