## ICSE Class 10 Mensuration MCQ New Pattern

*ICSE Class 10 Mensuration MCQ By Clarify Knowledge *

## ICSE Class 10 Mensuration MCQ Table

## OUR EBOOKS CAN HELP YOU ICSE CLASS 10 BOARD

## CODE IS EASY CAN HELP YOU IN SEMESTER 2

## Best Reference Books For Class 10 ICSE

*Best Reference Books For Class 10 ICSE Physics Is OSWAL GURUKUL*

## ICSE Class 10 All Subject MCQ

### ICSE Class 10 Mensuration MCQ HERE

**1. The shape of an ice-cream cone is a combination of:**

(a) Sphere + cylinder

(b) Sphere + cone

(c) Hemisphere + cylinder

(d) Hemisphere + cone

Answer: **(d) Hemisphere + cone**

The shape of an ice-cream cone is a combination of a hemisphere and a cone.

**2. If a cone is cut parallel to the base of it by a plane in two parts, then the shape of the top of the cone will be a:**

(a) Sphere

(b) Cube

(c) Cone itself

(d) Cylinder

Answer: **(c) Cone itself**

Explanation: If we cut a cone into two parts parallel to the base, then the shape of the upper part remains the same.

**3. If we cut a cone in two parts by a plane parallel to the base, then the bottom part left over is the:**

(a) Cone

(b) Frustum of cone

(c) Sphere

(d) Cylinder

Answer:** (b) Frustum of cone**

Explanation: See the figure below

**4. If r is the radius of the sphere, then the surface area of the sphere is given by;**

(a) 4 π r^{2}

(b) 2 π r^{2}

(c) π r^{2}

(d) 4/3 π r^{2}

Answer: (a) 4 π r^{2}

If r is the radius of the sphere, then the surface area of the sphere is given by 4 π r^{2}.

**5. If we change the shape of an object from a sphere to a cylinder, then the volume of cylinder will**

(a) Increase

(b) Decrease

(c) Remains unchanged

(d) Doubles

Answer: **(c) Remains unchanged**

Explanation: If we change the shape of a three-dimensional object, the volume of the new shape will be same.

**6. Fifteen solid spheres are made by melting a solid metallic cone of base diameter 2cm and height 15cm. The radius of each sphere is:**

(a) ½

(b) ¼

(c) 1/^{3}√2

(d) 1/^{3}√4

Answer: **(d) 1/ ^{3}√4**

Explanation: Volume of 15 spheres = Volume of a cone

15 x (4/3) π r^{3 }= ⅓ πr^{2}h

5×4 π r^{3 }= ⅓ π 1^{2}(15)

20r^{3 }= 5

r^{3 }= 5/20 = ¼

r = 1/^{3}√4

**7. The radius of the top and bottom of a bucket of slant height 35 cm are 25 cm and 8 cm. The curved surface of the bucket is:**

(a) 4000 sq.cm

(b) 3500 sq.cm

(c) 3630 sq.cm

(d) 3750 sq.cm

Answer: **(c) 3630 sq.cm**

Explanation: Curved surface of bucket = π(R_{1 }+ R_{2}) x slant height (l)

Curved Surface = (22/7) x (25 + 8) x 35

CSA = 22 x 33 x 5 = 3630 sq.cm.

**8. If a cylinder is covered by two hemispheres shaped lid of equal shape, then the total curved surface area of the new object will be**

(a) 4πrh + 2πr^{2}

(b) 4πrh – 2πr^{2}

(c) 2πrh + 4πr^{2}

(d) 2πrh + 4πr

Answer: **(c) 2πrh + 4πr ^{2}**

Explanation: Curved surface area of cylinder = 2πrh

The curved surface area of hemisphere = 2πr^{2}

Here, we have two hemispheres.

So, total curved surface area = 2πrh + 2(2πr^{2}) = 2πrh + 4πr^{2}

**9. A tank is made of the shape of a cylinder with a hemispherical depression at one end. The height of the cylinder is 1.45 m and radius is 30 cm. The total surface area of the tank is:**

(a) 30 m

(b) 3.3 m

(c) 30.3 m

(d) 3300 m

Answer: **(b) 3.3 m**

Explanation: Total surface area of tank = CSA of cylinder + CSA of hemisphere

= 2πrh + 2πr^{2}= 2π r(h + r)

= 2 x 22/7 x 30(145 + 30) cm^{2}

=33000 cm^{2}

= 3.3 m^{2}

**10. If we join two hemispheres of same radius along their bases, then we get a;**

(a) Cone

(b) Cylinder

(c) Sphere

(d) Cuboid

Answer: **(c) Sphere**